You can either put an additional resistor between DOUT and the LED, or you could simply change the 220 Ohm resistors on the DOUT for some of higher resistance. Higher resistance -> less current -> less brightness. Just don´t replace the DOUT resistors by “smaller” ones!
If you want to calculate the current:
I = (5VÂ - UL) / R
UL is the forward voltage of the LED. Standard types have around 1.5 V, blue and extra-bright LEDs often have more (2-4 Volts). The standard resistance of 220 Ohms gives (5V-1.5V)/220 = 16 mA of standard LEDs, which usually is a good value.
Replace them e.g. with 500 Ohm resistors and you´ll get 7 mA.