This cannot be answered directly, cause the resistance depends on where you measure (you have three, not two pins on a pot/fader).
With pots it´s alwasy like this (looking on the pot from *above*):
O
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1 2 3
Pin 1 goes to ground, Pin 2 is the signal, Pin 3 is + 5V. This means if the resistance is measurend between Pin 1 and 2 it should be zero if turned all counter-clockwise and 10 k clockwise. Between Pin 2 and 3 it´s the opposite.
Faders the same, just that they normally look like this (Pins are the same):
3-||
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2-||
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1-||
Resistance Pin 1 & 2 = 0 for fader turned downwards and 10 k for upwards.
i don’t want to create a panel where my faders will be running upside-down
Been there friend. 8)
Rest assured, if you accidentally did, I was given a fix here which wasn’t all that difficult (just a couple lines). Best to try not to do it in the first place anyway. ;D