Im going to use an IR device for my MidiBox64 and this IR is giving me a max output of 5.3 V does anybody know if this will damage the PIC or it will no work properly, and if so How can I solve it?!?!
Thanxs , ths forum is helping me to clarifie all my doubts
you should be able to fix it with the help of … 2 resistors :)
i’ll try a simple scheme you probably know (common electronics)
[pre]
______
>Vin>–|__R1__|--------------------->Vout
|R2|
--------------------------------------->ground[/pre]
correct me if i’m wrong but i think i remeber that :
Vout = R2/R1 * Vin
Vin is the output of your IR sensor
Vout goes to the PIC input
choose correctly your resistor and you should go ok !
RAF
Hello mferolla
I have just finished my first midibox. It is build for use with sensors. Until now it has 8 inputjacks on the top of the box.
Each input has a voltage protection, the one that Thorsten has described in the section “midibox extensions”. This should prevent voltages below -0.7 and above 5.7 to enter the pic.
In each protection unit I have omitted the two 10k resistors, because with the two 10k there would be a bias voltage 2.5v. Meaning the inputs would only go from 2.5 to 5v.
Considering Thorsten calls it a protection circuit, I should think that the pic can accept voltages inside
-0.7 to 5.7volts, but Im a musician not a electrician so I would like to know to!!
Bye Pelle Pelle
Thats correct - the data sheet says: long-term maximum voltage 5.5V, absolute maximum voltage (before damage): 7.5V
So, you can use the IR sensors without the prodection diodes if you are sure that 5.5V are not exceeted.
Best Regards, Thorsten.
Thanks now I m more relax!
mariano