There is nothing wrong with the PCB layout. PSU Option B works.
You are getting confused by the 9V DC being added to the 5V DC to produce 14V DC relative to ground.
doing this connect the 5V supply line reserved for the Cores to the ground, so no more supply
No, V1 common pin is not connected to ground.
In this wiring, V1 will regulate the input to 9V DC, 9V above the common pin which is 5V above ground.
Thus V1 output will be 14V above ground, as stated.
9V entering a 12v regulator can’t give 12v
As above, V1 is outputting 14V above ground, which is then connected to the V2 and V3 regulators, which have their common pin on ground.
i discovered this by soldering the base PCB and testing voltages.
The solution i found is not very elegant. don’t bridge as mentioned, i connect the input of V1 to the input of V3. But it bypass C12 and C11.
Better solution appreciated
You probably did not test the voltages correctly.
If you test the output of V1 relative to common pin (middle pin) it will be 9V. If you test the output of V1 relative to ground, it will be 14V (for PSU Option B).
To reiterate, in PSU Option B, the 9V AC from the PSU is rectified and regulated into 9V DC (by V1) but this 9V DC supply does not have the same ground as the rest of the PCB, V1 common pin is connected to 5V so that V1 outputs 14V relative to ground.
As mentioned in the wiki, PSU Option B is like the “C64 PSU Optimized” wiring diagram:
http://www.ucapps.de/mbhp/mbhp_8xsid_c64_psu_optimized.pdf
the only difference is a common 7809 and 7812 regulators supplying multiple SIDs instead of one regulator per SID module.